Local MP Reid wins change to Commons Speaker election rules
June 18, 2015Local MP Reid wins change to Commons Speaker election rules
June 18, 2015
Ottawa — The House of Commons Wednesday adopted Lanark-Frontenac-Lennox and Addington MP Scott Reid’s proposal to change the method by which it elects its senior official. The proposal, Motion M-489, provides that future elections for Speaker of the Commons will be held using a “preferential ballot.”
“Impartiality is the most important quality in a Speaker. Our rules should encourage candidates with that quality, blunt partisanship, and promote consensus. This change does all of that,” said Reid.
Reid was pleased that his motion, which passed by a 169 – 97 margin, was supported by members of all parties. “I think it adds to the sense of consensus that we saw Conservatives, New Democrats, Liberals and Greens—including three of the four party leaders—voting in support of this change,” he said.
A preferential ballot is one on which voters rank the candidates in order of preference, marking 1, 2, 3 and so on. When counted, the least popular candidates are eliminated, one at a time, and their first-preference ballots are then redistributed to the second choice indicated. This process repeats until one candidate achieves 50% of the vote.
Reid noted that the United Kingdom’s upper house, the House of Lords, has been using this system since it was reformed a decade ago, with positive results. “We’ve seen in the UK that candidates who are acceptable to everybody rise to the top. It is evident that the least partisan candidates attracted the largest number of second and third preferences, causing them to do better on later counts,” he said.
He added, “Preferential ballots for a post like Speaker eliminate the pressure to vote strategically—i.e. to vote negatively to block a disliked candidate—and instead encourage positive voting on the merits of the candidates.
Under the old system (known as the “exhaustive” ballot), there were multiple rounds of voting, which could take all day. The average Speakership election took seven hours. In the most extreme case, in 1986, there were eleven rounds of balloting. “The loss of an entire day for 338 MPs in the next Parliament would amount to an entire year of person-days,” observed Reid.
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For further information contact:
Dennis Laurie
Office of Scott Reid, M.P.
613-947-2277
BACKGROUND
Mr. Reid’s motion M-489 was implemented by way of the House of Commons concurring in the 21st report of the Standing Committee on Procedure and House Affairs.
The committee’s report can be found here:
The text of Mr. Reid’s motion M-489 can be found here:
M-489 — Election of the Speaker
That the Standing Committee on Procedure and House Affairs be instructed to consider the advisability of instituting a single, preferential ballot for the election of the Speaker by replacing Standing Order 4 with the following:
“4. The election of a Speaker shall be conducted by secret ballot as follows:
(1) Any Member who does not wish to be considered for election to the Office of Speaker shall, not later than 6:00 p.m. on the day preceding the day on which the election of a Speaker is expected to take place, in writing, so inform the Clerk of the House who shall prepare a list of such Members’ names together with a list of all Ministers of the Crown and party leaders, and shall provide the same to the Member presiding prior to the taking of the ballot.
(2) Members present in the Chamber shall be provided by the Clerk of the House with ballot papers, on which shall be listed, in alphabetical order, the names of all the Members whose names have not been placed on the list provided pursuant to section (1) of this Standing Order.
(3) The Member presiding shall announce from the Chair that the list provided pursuant to section (1) of this Standing Order is available for consultation at the Table.
(4) Members wishing to indicate their choice for the Office of Speaker shall rank each candidate listed on the ballot in the Member’s order of preference by marking the number “1” in the space adjacent to the name of the candidate who is the Member’s first preference, the number “2” in the space adjacent to the name of the Member’s second preference and so on until the Member has completed the ranking of all the candidates for whom the Member wishes to vote.
(5) A ballot on which a Member has ranked one or more, but not all, of the candidates is valid only in respect of the candidate or candidates whom the member has ranked.
(6) Members shall deposit their completed ballot papers in a box provided for that purpose on the Table.
(7) The Clerk of the House shall, once all Members wishing to do so have deposited their ballot papers, count the number of first preferences recorded on the ballots for each candidate, and, if a candidate has received a majority of first preferences, provide the Member presiding with the name of that candidate, whereupon the Member presiding shall announce the name of the new Speaker.
(8) If, after the count referred to in section (7) of this Standing Order, no candidate has received a majority of first preferences, the Clerk of the House shall (a) eliminate the candidate who received the least number of first preferences from any subsequent counts and, in the event that, at the conclusion of a count, there is an equality of votes between two or more candidates, both or all of whom have the fewest first preferences, eliminate all of the candidates for whom there is an equality of first preferences; (b) in all subsequent counts, treat each second or lower preference as if it were a first preference for the next highest candidate in the order of preference who is not eliminated; and (c) repeat the process of vote counting described in paragraphs (a) and (b) until one candidate has received a majority of first preferences, at which point the Clerk of the House shall provide the Member presiding with the name of that candidate, whereupon the Member presiding shall announce the name of the new Speaker.
(9) Every ballot shall be considered in every count, unless it is exhausted in accordance with section (10) of this Standing Order.
(10) A ballot is exhausted when all the candidates on that ballot in respect of which a preference has been made are eliminated.
(11) In the event that, after all other candidates have been eliminated, the process of vote counting has resulted in an equality of largest number of first preferences between two or more candidates, Members present in the Chamber shall be provided by the Clerk of the House with ballot papers, on which shall be listed, in alphabetical order, the names of all candidates who have not been eliminated, and the vote shall proceed in like manner as the first vote.
(12) After a Speaker has been declared elected, the Clerk of the House shall destroy the ballots together with all records of the number of preferences marked for each candidate and the Clerk of the House shall in no way divulge the number of preferences marked for any candidate.
(13) During the election of a Speaker there shall be no debate and the Member presiding shall not be permitted to entertain any question of privilege.”; and report its finding to the House no later than six months following the adoption of this order.
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